JMNR and JLPR are parallelograms and KQP is an isosceles triangle. Given that ∠KPL = 41°, ∠JRQ = 61° and ∠MPN = 51°, find
- ∠LPM,
- ∠MLP.
(a)
∠KPQ
= (180° - 21°) ÷ 2
= 79.5° (Isosceles triangle)
∠LPM
= 180° - 79.5° - 41° - 51°
= 8.5° (Angles on a straight line)
(b)
∠MLP
= 180° - 51° -8.5°
= 120.5° (Interior angles)
Answer(s): (a) 8.5°; (b) 120.5°