FJKN and FHLN are parallelograms and GML is an isosceles triangle. Given that ∠GLH = 37°, ∠FNM = 61° and ∠JLK = 51°, find
- ∠HLJ,
- ∠JHL.
(a)
∠GLM
= (180° - 22°) ÷ 2
= 79° (Isosceles triangle)
∠HLJ
= 180° - 79° - 37° - 51°
= 13° (Angles on a straight line)
(b)
∠JHL
= 180° - 51° -13°
= 116° (Interior angles)
Answer(s): (a) 13°; (b) 116°