KNPS and KMQS are parallelograms and LRQ is an isosceles triangle. Given that ∠LQM = 36°, ∠KSR = 65° and ∠NQP = 48°, find
- ∠MQN,
- ∠NMQ.
(a)
∠LQR
= (180° - 24°) ÷ 2
= 78° (Isosceles triangle)
∠MQN
= 180° - 78° - 36° - 48°
= 18° (Angles on a straight line)
(b)
∠NMQ
= 180° - 48° -18°
= 114° (Interior angles)
Answer(s): (a) 18°; (b) 114°