DGHL and DFJL are parallelograms and EKJ is an isosceles triangle. Given that ∠EJF = 42°, ∠DLK = 62° and ∠GJH = 52°, find
- ∠FJG,
- ∠GFJ.
(a)
∠EJK
= (180° - 25°) ÷ 2
= 77.5° (Isosceles triangle)
∠FJG
= 180° - 77.5° - 42° - 52°
= 8.5° (Angles on a straight line)
(b)
∠GFJ
= 180° - 52° -8.5°
= 119.5° (Interior angles)
Answer(s): (a) 8.5°; (b) 119.5°