JMNR and JLPR are parallelograms and KQP is an isosceles triangle. Given that ∠KPL = 38°, ∠JRQ = 62° and ∠MPN = 51°, find
- ∠LPM,
- ∠MLP.
(a)
∠KPQ
= (180° - 21°) ÷ 2
= 79.5° (Isosceles triangle)
∠LPM
= 180° - 79.5° - 38° - 51°
= 11.5° (Angles on a straight line)
(b)
∠MLP
= 180° - 51° -11.5°
= 117.5° (Interior angles)
Answer(s): (a) 11.5°; (b) 117.5°