EHJM and EGKM are parallelograms and FLK is an isosceles triangle. Given that ∠FKG = 41°, ∠EML = 62° and ∠HKJ = 48°, find
- ∠GKH,
- ∠HGK.
(a)
∠FKL
= (180° - 27°) ÷ 2
= 76.5° (Isosceles triangle)
∠GKH
= 180° - 76.5° - 41° - 48°
= 14.5° (Angles on a straight line)
(b)
∠HGK
= 180° - 48° -14.5°
= 117.5° (Interior angles)
Answer(s): (a) 14.5°; (b) 117.5°