BEFJ and BDGJ are parallelograms and CHG is an isosceles triangle. Given that ∠CGD = 40°, ∠BJH = 61° and ∠EGF = 49°, find
- ∠DGE,
- ∠EDG.
(a)
∠CGH
= (180° - 22°) ÷ 2
= 79° (Isosceles triangle)
∠DGE
= 180° - 79° - 40° - 49°
= 12° (Angles on a straight line)
(b)
∠EDG
= 180° - 49° -12°
= 119° (Interior angles)
Answer(s): (a) 12°; (b) 119°