HLMQ and HKNQ are parallelograms and JPN is an isosceles triangle. Given that ∠JNK = 41°, ∠HQP = 62° and ∠LNM = 46°, find
- ∠KNL,
- ∠LKN.
(a)
∠JNP
= (180° - 24°) ÷ 2
= 78° (Isosceles triangle)
∠KNL
= 180° - 78° - 41° - 46°
= 15° (Angles on a straight line)
(b)
∠LKN
= 180° - 46° -15°
= 119° (Interior angles)
Answer(s): (a) 15°; (b) 119°