BEFJ and BDGJ are parallelograms and CHG is an isosceles triangle. Given that ∠CGD = 38°, ∠BJH = 64° and ∠EGF = 50°, find
- ∠DGE,
- ∠EDG.
(a)
∠CGH
= (180° - 24°) ÷ 2
= 78° (Isosceles triangle)
∠DGE
= 180° - 78° - 38° - 50°
= 14° (Angles on a straight line)
(b)
∠EDG
= 180° - 50° -14°
= 116° (Interior angles)
Answer(s): (a) 14°; (b) 116°