FJKN and FHLN are parallelograms and GML is an isosceles triangle. Given that ∠GLH = 40°, ∠FNM = 65° and ∠JLK = 49°, find
- ∠HLJ,
- ∠JHL.
(a)
∠GLM
= (180° - 22°) ÷ 2
= 79° (Isosceles triangle)
∠HLJ
= 180° - 79° - 40° - 49°
= 12° (Angles on a straight line)
(b)
∠JHL
= 180° - 49° -12°
= 119° (Interior angles)
Answer(s): (a) 12°; (b) 119°