JMNR and JLPR are parallelograms and KQP is an isosceles triangle. Given that ∠KPL = 38°, ∠JRQ = 65° and ∠MPN = 47°, find
- ∠LPM,
- ∠MLP.
(a)
∠KPQ
= (180° - 22°) ÷ 2
= 79° (Isosceles triangle)
∠LPM
= 180° - 79° - 38° - 47°
= 16° (Angles on a straight line)
(b)
∠MLP
= 180° - 47° -16°
= 117° (Interior angles)
Answer(s): (a) 16°; (b) 117°