MQRU and MPSU are parallelograms and NTS is an isosceles triangle. Given that ∠NSP = 39°, ∠MUT = 63° and ∠QSR = 50°, find
- ∠PSQ,
- ∠QPS.
(a)
∠NST
= (180° - 23°) ÷ 2
= 78.5° (Isosceles triangle)
∠PSQ
= 180° - 78.5° - 39° - 50°
= 12.5° (Angles on a straight line)
(b)
∠QPS
= 180° - 50° -12.5°
= 117.5° (Interior angles)
Answer(s): (a) 12.5°; (b) 117.5°