JMNR and JLPR are parallelograms and KQP is an isosceles triangle. Given that ∠KPL = 36°, ∠JRQ = 64° and ∠MPN = 50°, find
- ∠LPM,
- ∠MLP.
(a)
∠KPQ
= (180° - 27°) ÷ 2
= 76.5° (Isosceles triangle)
∠LPM
= 180° - 76.5° - 36° - 50°
= 17.5° (Angles on a straight line)
(b)
∠MLP
= 180° - 50° -17.5°
= 112.5° (Interior angles)
Answer(s): (a) 17.5°; (b) 112.5°