MQRU and MPSU are parallelograms and NTS is an isosceles triangle. Given that ∠NSP = 36°, ∠MUT = 61° and ∠QSR = 46°, find
- ∠PSQ,
- ∠QPS.
(a)
∠NST
= (180° - 24°) ÷ 2
= 78° (Isosceles triangle)
∠PSQ
= 180° - 78° - 36° - 46°
= 20° (Angles on a straight line)
(b)
∠QPS
= 180° - 46° -20°
= 114° (Interior angles)
Answer(s): (a) 20°; (b) 114°