JMNR and JLPR are parallelograms and KQP is an isosceles triangle. Given that ∠KPL = 40°, ∠JRQ = 63° and ∠MPN = 47°, find
- ∠LPM,
- ∠MLP.
(a)
∠KPQ
= (180° - 23°) ÷ 2
= 78.5° (Isosceles triangle)
∠LPM
= 180° - 78.5° - 40° - 47°
= 14.5° (Angles on a straight line)
(b)
∠MLP
= 180° - 47° -14.5°
= 118.5° (Interior angles)
Answer(s): (a) 14.5°; (b) 118.5°