KNPS and KMQS are parallelograms and LRQ is an isosceles triangle. Given that ∠LQM = 42°, ∠KSR = 62° and ∠NQP = 50°, find
- ∠MQN,
- ∠NMQ.
(a)
∠LQR
= (180° - 21°) ÷ 2
= 79.5° (Isosceles triangle)
∠MQN
= 180° - 79.5° - 42° - 50°
= 8.5° (Angles on a straight line)
(b)
∠NMQ
= 180° - 50° -8.5°
= 121.5° (Interior angles)
Answer(s): (a) 8.5°; (b) 121.5°