FJKN and FHLN are parallelograms and GML is an isosceles triangle. Given that ∠GLH = 40°, ∠FNM = 65° and ∠JLK = 49°, find
- ∠HLJ,
- ∠JHL.
(a)
∠GLM
= (180° - 26°) ÷ 2
= 77° (Isosceles triangle)
∠HLJ
= 180° - 77° - 40° - 49°
= 14° (Angles on a straight line)
(b)
∠JHL
= 180° - 49° -14°
= 117° (Interior angles)
Answer(s): (a) 14°; (b) 117°