JMNR and JLPR are parallelograms and KQP is an isosceles triangle. Given that ∠KPL = 42°, ∠JRQ = 62° and ∠MPN = 52°, find
- ∠LPM,
- ∠MLP.
(a)
∠KPQ
= (180° - 24°) ÷ 2
= 78° (Isosceles triangle)
∠LPM
= 180° - 78° - 42° - 52°
= 8° (Angles on a straight line)
(b)
∠MLP
= 180° - 52° -8°
= 120° (Interior angles)
Answer(s): (a) 8°; (b) 120°