JMNR and JLPR are parallelograms and KQP is an isosceles triangle. Given that ∠KPL = 40°, ∠JRQ = 64° and ∠MPN = 50°, find
- ∠LPM,
- ∠MLP.
(a)
∠KPQ
= (180° - 24°) ÷ 2
= 78° (Isosceles triangle)
∠LPM
= 180° - 78° - 40° - 50°
= 12° (Angles on a straight line)
(b)
∠MLP
= 180° - 50° -12°
= 118° (Interior angles)
Answer(s): (a) 12°; (b) 118°