DGHL and DFJL are parallelograms and EKJ is an isosceles triangle. Given that ∠EJF = 42°, ∠DLK = 65° and ∠GJH = 50°, find
- ∠FJG,
- ∠GFJ.
(a)
∠EJK
= (180° - 22°) ÷ 2
= 79° (Isosceles triangle)
∠FJG
= 180° - 79° - 42° - 50°
= 9° (Angles on a straight line)
(b)
∠GFJ
= 180° - 50° -9°
= 121° (Interior angles)
Answer(s): (a) 9°; (b) 121°