HLMQ and HKNQ are parallelograms and JPN is an isosceles triangle. Given that ∠JNK = 40°, ∠HQP = 64° and ∠LNM = 48°, find
- ∠KNL,
- ∠LKN.
(a)
∠JNP
= (180° - 26°) ÷ 2
= 77° (Isosceles triangle)
∠KNL
= 180° - 77° - 40° - 48°
= 15° (Angles on a straight line)
(b)
∠LKN
= 180° - 48° -15°
= 117° (Interior angles)
Answer(s): (a) 15°; (b) 117°