MQRU and MPSU are parallelograms and NTS is an isosceles triangle. Given that ∠NSP = 40°, ∠MUT = 63° and ∠QSR = 46°, find
- ∠PSQ,
- ∠QPS.
(a)
∠NST
= (180° - 22°) ÷ 2
= 79° (Isosceles triangle)
∠PSQ
= 180° - 79° - 40° - 46°
= 15° (Angles on a straight line)
(b)
∠QPS
= 180° - 46° -15°
= 119° (Interior angles)
Answer(s): (a) 15°; (b) 119°