HLMQ and HKNQ are parallelograms and JPN is an isosceles triangle. Given that ∠JNK = 42°, ∠HQP = 61° and ∠LNM = 51°, find
- ∠KNL,
- ∠LKN.
(a)
∠JNP
= (180° - 21°) ÷ 2
= 79.5° (Isosceles triangle)
∠KNL
= 180° - 79.5° - 42° - 51°
= 7.5° (Angles on a straight line)
(b)
∠LKN
= 180° - 51° -7.5°
= 121.5° (Interior angles)
Answer(s): (a) 7.5°; (b) 121.5°