BEFJ and BDGJ are parallelograms and CHG is an isosceles triangle. Given that ∠CGD = 39°, ∠BJH = 65° and ∠EGF = 46°, find
- ∠DGE,
- ∠EDG.
(a)
∠CGH
= (180° - 21°) ÷ 2
= 79.5° (Isosceles triangle)
∠DGE
= 180° - 79.5° - 39° - 46°
= 15.5° (Angles on a straight line)
(b)
∠EDG
= 180° - 46° -15.5°
= 118.5° (Interior angles)
Answer(s): (a) 15.5°; (b) 118.5°