DGHL and DFJL are parallelograms and EKJ is an isosceles triangle. Given that ∠EJF = 36°, ∠DLK = 65° and ∠GJH = 46°, find
- ∠FJG,
- ∠GFJ.
(a)
∠EJK
= (180° - 23°) ÷ 2
= 78.5° (Isosceles triangle)
∠FJG
= 180° - 78.5° - 36° - 46°
= 19.5° (Angles on a straight line)
(b)
∠GFJ
= 180° - 46° -19.5°
= 114.5° (Interior angles)
Answer(s): (a) 19.5°; (b) 114.5°