BEFJ and BDGJ are parallelograms and CHG is an isosceles triangle. Given that ∠CGD = 37°, ∠BJH = 64° and ∠EGF = 46°, find
- ∠DGE,
- ∠EDG.
(a)
∠CGH
= (180° - 26°) ÷ 2
= 77° (Isosceles triangle)
∠DGE
= 180° - 77° - 37° - 46°
= 20° (Angles on a straight line)
(b)
∠EDG
= 180° - 46° -20°
= 114° (Interior angles)
Answer(s): (a) 20°; (b) 114°