KNPS and KMQS are parallelograms and LRQ is an isosceles triangle. Given that ∠LQM = 39°, ∠KSR = 64° and ∠NQP = 47°, find
- ∠MQN,
- ∠NMQ.
(a)
∠LQR
= (180° - 23°) ÷ 2
= 78.5° (Isosceles triangle)
∠MQN
= 180° - 78.5° - 39° - 47°
= 15.5° (Angles on a straight line)
(b)
∠NMQ
= 180° - 47° -15.5°
= 117.5° (Interior angles)
Answer(s): (a) 15.5°; (b) 117.5°