HLMQ and HKNQ are parallelograms and JPN is an isosceles triangle. Given that ∠JNK = 41°, ∠HQP = 64° and ∠LNM = 47°, find
- ∠KNL,
- ∠LKN.
(a)
∠JNP
= (180° - 23°) ÷ 2
= 78.5° (Isosceles triangle)
∠KNL
= 180° - 78.5° - 41° - 47°
= 13.5° (Angles on a straight line)
(b)
∠LKN
= 180° - 47° -13.5°
= 119.5° (Interior angles)
Answer(s): (a) 13.5°; (b) 119.5°