DGHL and DFJL are parallelograms and EKJ is an isosceles triangle. Given that ∠EJF = 38°, ∠DLK = 63° and ∠GJH = 49°, find
- ∠FJG,
- ∠GFJ.
(a)
∠EJK
= (180° - 21°) ÷ 2
= 79.5° (Isosceles triangle)
∠FJG
= 180° - 79.5° - 38° - 49°
= 13.5° (Angles on a straight line)
(b)
∠GFJ
= 180° - 49° -13.5°
= 117.5° (Interior angles)
Answer(s): (a) 13.5°; (b) 117.5°