GKLP and GJMP are parallelograms and HNM is an isosceles triangle. Given that ∠HMJ = 40°, ∠GPN = 61° and ∠KML = 49°, find
- ∠JMK,
- ∠KJM.
(a)
∠HMN
= (180° - 25°) ÷ 2
= 77.5° (Isosceles triangle)
∠JMK
= 180° - 77.5° - 40° - 49°
= 13.5° (Angles on a straight line)
(b)
∠KJM
= 180° - 49° -13.5°
= 117.5° (Interior angles)
Answer(s): (a) 13.5°; (b) 117.5°