FJKN and FHLN are parallelograms and GML is an isosceles triangle. Given that ∠GLH = 36°, ∠FNM = 64° and ∠JLK = 51°, find
- ∠HLJ,
- ∠JHL.
(a)
∠GLM
= (180° - 23°) ÷ 2
= 78.5° (Isosceles triangle)
∠HLJ
= 180° - 78.5° - 36° - 51°
= 14.5° (Angles on a straight line)
(b)
∠JHL
= 180° - 51° -14.5°
= 114.5° (Interior angles)
Answer(s): (a) 14.5°; (b) 114.5°