BEFJ and BDGJ are parallelograms and CHG is an isosceles triangle. Given that ∠CGD = 42°, ∠BJH = 65° and ∠EGF = 52°, find
- ∠DGE,
- ∠EDG.
(a)
∠CGH
= (180° - 22°) ÷ 2
= 79° (Isosceles triangle)
∠DGE
= 180° - 79° - 42° - 52°
= 7° (Angles on a straight line)
(b)
∠EDG
= 180° - 52° -7°
= 121° (Interior angles)
Answer(s): (a) 7°; (b) 121°