In the figure, PHKN and PHJM are parallelograms. Given that ∠KHL = 13°, ∠PNM = 70° and PMN is an isosceles triangle where PM = PN. Find
- ∠HLK
- ∠PHL
(a)
∠HKN
= 180° - 70°
= 110° (Interior angles)
∠HLK
= 180° - 110° - 13°
= 57° (Angles sum of triangle)
(b)
∠PHL
= ∠HLK
= 57° (Alternate angles)
Answer(s): (a) 57°; (b) 57°