In the figure, WQSV and WQRU are parallelograms. Given that ∠SQT = 13°, ∠WVU = 76° and WUV is an isosceles triangle where WU = WV. Find
- ∠QTS
- ∠WQT
(a)
∠QSV
= 180° - 76°
= 104° (Interior angles)
∠QTS
= 180° - 104° - 13°
= 63° (Angles sum of triangle)
(b)
∠WQT
= ∠QTS
= 63° (Alternate angles)
Answer(s): (a) 63°; (b) 63°