In the figure, PHKN and PHJM are parallelograms. Given that ∠KHL = 16°, ∠PNM = 64° and PMN is an isosceles triangle where PM = PN. Find
- ∠HLK
- ∠PHL
(a)
∠HKN
= 180° - 64°
= 116° (Interior angles)
∠HLK
= 180° - 116° - 16°
= 48° (Angles sum of triangle)
(b)
∠PHL
= ∠HLK
= 48° (Alternate angles)
Answer(s): (a) 48°; (b) 48°