In the figure, ZTVY and ZTUX are parallelograms. Given that ∠VTW = 15°, ∠ZYX = 70° and ZXY is an isosceles triangle where ZX = ZY. Find
- ∠TWV
- ∠ZTW
(a)
∠TVY
= 180° - 70°
= 110° (Interior angles)
∠TWV
= 180° - 110° - 15°
= 55° (Angles sum of triangle)
(b)
∠ZTW
= ∠TWV
= 55° (Alternate angles)
Answer(s): (a) 55°; (b) 55°