In the figure, UNQT and UNPS are parallelograms. Given that ∠QNR = 14°, ∠UTS = 73° and UST is an isosceles triangle where US = UT. Find
- ∠NRQ
- ∠UNR
(a)
∠NQT
= 180° - 73°
= 107° (Interior angles)
∠NRQ
= 180° - 107° - 14°
= 59° (Angles sum of triangle)
(b)
∠UNR
= ∠NRQ
= 59° (Alternate angles)
Answer(s): (a) 59°; (b) 59°