In the figure, WQSV and WQRU are parallelograms. Given that ∠SQT = 13°, ∠WVU = 60° and WUV is an isosceles triangle where WU = WV. Find
- ∠QTS
- ∠WQT
(a)
∠QSV
= 180° - 60°
= 120° (Interior angles)
∠QTS
= 180° - 120° - 13°
= 47° (Angles sum of triangle)
(b)
∠WQT
= ∠QTS
= 47° (Alternate angles)
Answer(s): (a) 47°; (b) 47°