In the figure, LEGK and LEFJ are parallelograms. Given that ∠GEH = 13°, ∠LKJ = 79° and LJK is an isosceles triangle where LJ = LK. Find
- ∠EHG
- ∠LEH
(a)
∠EGK
= 180° - 79°
= 101° (Interior angles)
∠EHG
= 180° - 101° - 13°
= 66° (Angles sum of triangle)
(b)
∠LEH
= ∠EHG
= 66° (Alternate angles)
Answer(s): (a) 66°; (b) 66°