In the figure, TMPS and TMNR are parallelograms. Given that ∠PMQ = 14°, ∠TSR = 61° and TRS is an isosceles triangle where TR = TS. Find
- ∠MQP
- ∠TMQ
(a)
∠MPS
= 180° - 61°
= 119° (Interior angles)
∠MQP
= 180° - 119° - 14°
= 47° (Angles sum of triangle)
(b)
∠TMQ
= ∠MQP
= 47° (Alternate angles)
Answer(s): (a) 47°; (b) 47°