In the figure, TMPS and TMNR are parallelograms. Given that ∠PMQ = 14°, ∠TSR = 70° and TRS is an isosceles triangle where TR = TS. Find
- ∠MQP
- ∠TMQ
(a)
∠MPS
= 180° - 70°
= 110° (Interior angles)
∠MQP
= 180° - 110° - 14°
= 56° (Angles sum of triangle)
(b)
∠TMQ
= ∠MQP
= 56° (Alternate angles)
Answer(s): (a) 56°; (b) 56°