In the figure, QJLP and QJKN are parallelograms. Given that ∠LJM = 11°, ∠QPN = 78° and QNP is an isosceles triangle where QN = QP. Find
- ∠JML
- ∠QJM
(a)
∠JLP
= 180° - 78°
= 102° (Interior angles)
∠JML
= 180° - 102° - 11°
= 67° (Angles sum of triangle)
(b)
∠QJM
= ∠JML
= 67° (Alternate angles)
Answer(s): (a) 67°; (b) 67°