In the figure, KDFJ and KDEH are parallelograms. Given that ∠FDG = 11°, ∠KJH = 76° and KHJ is an isosceles triangle where KH = KJ. Find
- ∠DGF
- ∠KDG
(a)
∠DFJ
= 180° - 76°
= 104° (Interior angles)
∠DGF
= 180° - 104° - 11°
= 65° (Angles sum of triangle)
(b)
∠KDG
= ∠DGF
= 65° (Alternate angles)
Answer(s): (a) 65°; (b) 65°