In the figure, VPRU and VPQT are parallelograms. Given that ∠RPS = 16°, ∠VUT = 70° and VTU is an isosceles triangle where VT = VU. Find
- ∠PSR
- ∠VPS
(a)
∠PRU
= 180° - 70°
= 110° (Interior angles)
∠PSR
= 180° - 110° - 16°
= 54° (Angles sum of triangle)
(b)
∠VPS
= ∠PSR
= 54° (Alternate angles)
Answer(s): (a) 54°; (b) 54°