In the figure, RKMQ and RKLP are parallelograms. Given that ∠MKN = 11°, ∠RQP = 70° and RPQ is an isosceles triangle where RP = RQ. Find
- ∠KNM
- ∠RKN
(a)
∠KMQ
= 180° - 70°
= 110° (Interior angles)
∠KNM
= 180° - 110° - 11°
= 59° (Angles sum of triangle)
(b)
∠RKN
= ∠KNM
= 59° (Alternate angles)
Answer(s): (a) 59°; (b) 59°