In the figure, SLNR and SLMQ are parallelograms. Given that ∠NLP = 11°, ∠SRQ = 79° and SQR is an isosceles triangle where SQ = SR. Find
- ∠LPN
- ∠SLP
(a)
∠LNR
= 180° - 79°
= 101° (Interior angles)
∠LPN
= 180° - 101° - 11°
= 68° (Angles sum of triangle)
(b)
∠SLP
= ∠LPN
= 68° (Alternate angles)
Answer(s): (a) 68°; (b) 68°