In the figure, LEGK and LEFJ are parallelograms. Given that ∠GEH = 14°, ∠LKJ = 74° and LJK is an isosceles triangle where LJ = LK. Find
- ∠EHG
- ∠LEH
(a)
∠EGK
= 180° - 74°
= 106° (Interior angles)
∠EHG
= 180° - 106° - 14°
= 60° (Angles sum of triangle)
(b)
∠LEH
= ∠EHG
= 60° (Alternate angles)
Answer(s): (a) 60°; (b) 60°