In the figure, WQSV and WQRU are parallelograms. Given that ∠SQT = 14°, ∠WVU = 69° and WUV is an isosceles triangle where WU = WV. Find
- ∠QTS
- ∠WQT
(a)
∠QSV
= 180° - 69°
= 111° (Interior angles)
∠QTS
= 180° - 111° - 14°
= 55° (Angles sum of triangle)
(b)
∠WQT
= ∠QTS
= 55° (Alternate angles)
Answer(s): (a) 55°; (b) 55°