In the figure, MFHL and MFGK are parallelograms. Given that ∠HFJ = 12°, ∠MLK = 78° and MKL is an isosceles triangle where MK = ML. Find
- ∠FJH
- ∠MFJ
(a)
∠FHL
= 180° - 78°
= 102° (Interior angles)
∠FJH
= 180° - 102° - 12°
= 66° (Angles sum of triangle)
(b)
∠MFJ
= ∠FJH
= 66° (Alternate angles)
Answer(s): (a) 66°; (b) 66°