In the figure, RKMQ and RKLP are parallelograms. Given that ∠MKN = 16°, ∠RQP = 67° and RPQ is an isosceles triangle where RP = RQ. Find
- ∠KNM
- ∠RKN
(a)
∠KMQ
= 180° - 67°
= 113° (Interior angles)
∠KNM
= 180° - 113° - 16°
= 51° (Angles sum of triangle)
(b)
∠RKN
= ∠KNM
= 51° (Alternate angles)
Answer(s): (a) 51°; (b) 51°